返回列表 發帖

Rank: 7Rank: 7Rank: 7
1# 跳轉到 » 倒序看帖
打印
tT
鄭繼威發表於 2022-7-19 02:27 | 只看該作者

for 迴圈 (二)

假設有一串列其內容如下：
list=["忠","孝","仁","愛","信","義","和","平"]

試以for迴圈，橫向顯示串列中的所有元素。

  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
複製代碼
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
複製代碼
收藏 分享

Rank: 1
2#
盧宥廷發表於 2022-7-19 14:48 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in list:
  3.     print(i,end=" ")
複製代碼

TOP

Rank: 1
3#
張晏齊發表於 2022-7-19 14:48 | 只看該作者
  1. # -*- coding: utf-8 -*-
  2. """
  3. Spyder Editor

  5. This is a temporary script file.
  6. """
  7. list1 =["忠","孝","仁","愛","信","義","和","平"]
  8. for s in list:
  9.     print(s,end=)
複製代碼

TOP

Rank: 1
4#
李宥廷發表於 2022-7-19 14:48 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for a in list:
  3.     print(a,end=" ")
複製代碼

TOP

Rank: 1
5#
陳羨芮發表於 2022-7-19 14:50 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
複製代碼

TOP

Rank: 1
6#
盧宥熏發表於 2022-7-19 14:50 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
複製代碼

TOP

返回列表