TQC104 ~ TQC106 答案

TQC104
public class TQC104 {4 y5 d+ l) |& _4 h
  public static void main(String[] args) {
int a[]={0,1,2,3,4,5,6,7,8,9};
boolean check=false;3 p$ a0 o0 Y2 k' L: j5 ?
int i,j,c1,c2,c3,r1,r2,r3,x1,x2;
do{
   for( i=1 ; i<a.length ; i++){3 r  K" s7 @+ p! u0 L
      j=(int)(Math.random()*9)+1;! W: \4 z5 k) K6 z/ P2 Z4 r
      a[0] = a[i];
      a[i] = a[j];7 x3 D% r- [3 u, ?) S
      a[j] = a[0];
   }2 }5 p  m! J+ j7 X0 D! r
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   c1=a[1]+a[2]+a[3];
   c2=a[4]+a[5]+a[6];
   c3=a[7]+a[8]+a[9];7 l3 ^3 o, J9 D$ b3 J7 h0 B' Y  X
   r1=a[1]+a[4]+a[7];
   r2=a[2]+a[5]+a[8];$ ]* c) d# N8 [
   r3=a[3]+a[6]+a[9];
   x1=a[1]+a[5]+a[9];  a# Z  b) R3 B- C! Y& o4 O
   x2=a[3]+a[5]+a[7];
   if( c1==15 && c2==15 && c3==15 && r1==15 && r2==15 && r3==15
      && x1==15 && x2==15){
      check=true;8 J% Y# e# `: S8 }0 x9 X4 h
   }6 ]! |  S+ d4 _0 M1 s2 b& E* j2 A
}while(check==false);
System.out.println("答案為:");4 i, y: n5 O8 K. q

   System.out.println(a[1] + " " + a[2] + " " + a[3] );* Z5 Y3 k1 I5 [$ E) c7 A- N
   System.out.println(a[4] + " " + a[5] + " " + a[6] );
   System.out.println(a[7] + " " + a[8] + " " + a[9] );* j6 c0 c4 D" F
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System.out.println("不論橫向縱向及對角線加起來的和都是:15");, a' H" @2 O& Q9 r! Y+ }& F* \2 A
  }
}1 g6 y6 v/ U, m

TQC105
import java.io.*;6 L, E$ S  ^' ]/ Y  x
public class TQC105 {9 f2 T6 X3 [+ W: P$ S

  public static void main(String[] args){) K# L1 l+ c. K8 @0 f
try{
   int row,col;( Q0 K$ P5 Y$ f! c1 S3 {0 W
   int i,j;9 f3 [* I/ e6 W' J" x9 v% p
   String tmp;
   int aryA[][];
   int aryB[][];4 a8 c& l' R# p
   BufferedReader bin = new BufferedReader(new InputStreamReader(System.in));
  * J/ E% M, {! C, ^  x+ d# S" [- _
   System.out.println("請輸入陣列列數:");- d% e8 }* ?' R9 x1 D
   row = Integer.parseInt(bin.readLine());1 F9 j+ F& X8 g& Y" u% x5 h  D. D' c  U
   System.out.println("每一列陣列裡要幾個數字:");
   col = Integer.parseInt(bin.readLine());
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   aryA = new int[row][col];, X' a- ?2 z- S- V
   aryB = new int[col][row];" Z+ J. H8 g8 v; h

   for( i=0 ; i<row ; i++){
      System.out.println("請輸入第 "+ i +"列");7 [0 _& h! b) ]& s& t' ]" P
      tmp = bin.readLine();
      String[] strA = tmp.split(" ");% {- b# O- u  h7 h' g
      for( j=0 ; j<col ; j++ ){+ R" a% f3 G6 I& P8 p+ n' N
         aryA[i][j]=Integer.parseInt(strA[j]);
      }+ _' J, @3 R) O+ V3 @" e# z' @6 d
   }8 ?! A, n& i- {3 r; _, u$ Y$ C
   for( i=0 ; i<row ; i++){/ N" n; P3 s3 I0 o# F' t" `
      for( j=0 ; j<col ; j++){4 D9 U* v& Q8 @4 D8 X. E
         aryB[j][i]=aryA[i][j];
      }
   }
  ! R6 g* ~/ A( G
   System.out.println("陣列經行列轉換結果");
   for( i=0 ; i<col ; i++){3 E, x' K" U0 D
      for( j=0 ; j<row ; j++){
         System.out.print(aryA[j][i] + " ");+ p& A$ t/ W5 {; p- K6 O- z
      }# L+ K+ t3 O. u' \
      System.out.println();1 f: {# @, r+ |  @
   }
}catch(Exception e){
   System.out.println("請輸入數字");
   e.printStackTrace();
}

  }! y: i% |9 G' d4 z6 Y# `
}

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TQC1068 t+ O- u' w) X5 G4 H
public class TQC106- y3 x2 k: g& H$ r
{, c) I: d3 F2 N
public static void main(String args[])0 J8 A! z4 X( O$ {" s
{: U: v, b: ?0 [! X" C  U! V
   int sum = 0;
   int j =  0;
   int k =  0;% V6 i2 d- D/ ^& e) b3 M
   for(int i=0 ; i<args.length ; i++){  H( m( k& x1 a4 C
      try{
         sum += Integer.parseInt(args[i]);
         j++;
      }
      catch(NumberFormatException e){
         k++;5 F/ n' e' Y' T$ P6 L  x# i
      }) a- L" P* R& N" o$ h2 S
   }! k: L0 i/ r7 q6 A* {
   System.out.println("數值之總合為:" + sum );8 R0 h. o5 T& ?4 [* J
   System.out.println("非數值個數為:" + k );
   System.out.println("純數值個數為:" + j );* G( ~8 U7 a* @
}
}

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TQC104 ~ TQC106 答案

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