C++第二題：計算兩個時間 (時:分:秒) 的間隔秒數。

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C++第二題：計算兩個時間 (時:分:秒) 的間隔秒數。

1. /*2.計算兩個時間 (時:分:秒) 的間隔秒數。*/
   
2. #include <iostream>
   
3. using namespace std;
   
4. int main(void){
   
5.    
   
6.     int h1, h2, m1, m2, s1, s2, time_1, time_2, time;
   
7.    
   
8.     cout << "Please enter first time : " << endl;
   
9.     cout << "Hours : " << endl;
   
10.     cin >> h1;
    
11.     cout << "Minutes : " << endl;
    
12.     cin >> m1;
    
13.     cout << "Seconds : " << endl;
    
14.     cin >> s1;
    
15.    
    
16.     cout << "Please enter senond time : " << endl;
    
17.     cout << "Hours : " << endl;
    
18.     cin >> h2;
    
19.     cout << "Minutes : " << endl;
    
20.     cin >> m2;
    
21.     cout << "Seconds : " << endl;
    
22.     cin >> s2;
    
23.    
    
24.     time_1 = h1*3600 + m1*60 + s1;  // the total seconds
    
25.     time_2 = h2*3600 + m2*60 + s2;  // the total seconds
    
26.    
    
27.     if(time_1 > time_2){
    
28.              time = time_1 - time_2;
    
29.     }else if(time_1 < time_2){
    
30.                 time = time_2 - time_1;
    
31.     }else if(time_1 == time_2){
    
32.           cout << "兩個時間相差零秒。" << endl;
    
33.     }
    
34.    
    
35.     cout << "兩個時間相差" << endl;
    
36.     cout << time / 3600 << " : ";  // get hours
    
37.     time = time - ((time / 3600) * 3600);  // get second cut hours
    
38.     cout << time / 60 << " : ";  // get Minutes
    
39.     time = time - ((time / 60) * 60);  // get second cut Minutes
    
40.     cout << time;  // seconds
    
41.    
    
42.     system("pause");
    
43.     return 0;
    
44. }

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