for 迴圈 (三)

鄭繼威

#range(start,stop,step)
#range(1,6)->[1,2,3,4,5]
試宣告兩個串列，一個存放班級名稱，一個存放人數，搭配 for 迴圈顯示五年級各班人數，執行畫面如下：

1. list1=["忠","孝","仁","愛","信","義","和","平"]
   
2. list2=[28,27,27,26,28,29,30,27]
   
3. for i in range(8):
   
4.     print("五年{}班有{}人".format(list1[i],list2[i]))

複製代碼

李宥廷

1. list1=b=["忠","孝","仁","愛","信","義","和","平"]
   
2. list2=c=[28,27,27,26,28,29,30,27]
   
3. for a in range(8):
   
4.     print(f"五年{b[a]}有{c[a]}人")

複製代碼

盧宥廷

1. list1=["忠","孝","仁","愛","信","義","和","平"]
   
2. list2=[28,27,27,26,28,29,30,27]
   
3. for i in range(0,8):
   
4.     print(f"五年{list1[i]}班有{list2[i]}人")

複製代碼

陳羨芮

1. list1=["忠","孝","仁","愛","信","義","和","平"]
   
2. list2=[28,27,27,26,28,29,30,27]
   
3. for i in range(8):
   
4.     print(f"五年{list1[i]}班有{list2[i]}人")

複製代碼

盧宥熏

1. list1=["忠","孝","仁","愛","信","義","和","平"]
   
2. list2=[28,27,27,26,28,29,30,27]
   
3. for i in range (0,8):
   
4.     print(f"五年{list1[i]}班有{list2[i]}人")

複製代碼

張晏齊

1. # -*- coding: utf-8 -*-
   
2. """
   
3. Spyder Editor
   
4. 
   
5. This is a temporary script file.
   
6. """
   
7. list1=["忠","孝","仁","愛","信","義","和","平"]
   
8. list2=[28,27,27,26,28,29,30,27]
   
9. 
   
10. 
    
11. #range(0,8)->[0...7]
    
12. for i in range(0,8):
    
13.     print(f"五年{list1[i]}班有{list2[i]}人")

複製代碼

鄭繼威

1. list1=["忠","孝","仁","愛","信","義","和","平"]
   
2. list2=[28,27,27,26,28,29,30,27]
   
3. 
   
4. #range(0,8)->[0...7]
   
5. for i in range(0,8):
   
6.     print(f"五年{list1[i]}班有{list2[i]}人")

複製代碼