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鄭繼威發表於 2022-8-18 22:25 | 只看該作者

for 迴圈 (二)

假設有一串列其內容如下：
list=["忠","孝","仁","愛","信","義","和","平"]

試以for迴圈，橫向顯示串列中的所有元素。

  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
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  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):
  3.     print(list[i],end=" ")
複製代碼
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8#
簡宗漢發表於 2022-8-19 14:51 | 只看該作者
  1. j=["忠","孝","仁","愛","信","義","和","平"]
  2. for p in range(0,4):
  3.     print(j[p],end="")
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7#
胡凰月發表於 2022-8-19 14:36 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for i in range(0,8):   
  3.     print(list[i],end=" ")
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6#
吳鎧茵發表於 2022-8-19 14:35 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
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5#
彭郁程發表於 2022-8-19 14:34 | 只看該作者
  1. list=["甲","乙","丙","丁","戊","己","庚","辛"]
  2. for s in list:
  3.     print(s,end=" ")
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4#
姜宏叡發表於 2022-8-19 14:34 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
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3#
吳俊頡發表於 2022-8-19 14:33 | 只看該作者
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
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2#
陳牧謙發表於 2022-8-19 14:33 | 只看該作者
本帖最後由 鄭繼威 於 2022-8-19 14:52 編輯
  1. list=["忠","孝","仁","愛","信","義","和","平"]
  2. for s in list:
  3.     print(s,end=" ")
複製代碼

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